greedy math *1000

Please click on ads to support us..

Python Code:

t = int(input())

for j in range(t):
    n = int(input())
    if (n%4 != 0):
        m = n//4 + 1
    else:
        m = n//4
    n = n-m
    a = ''
    for j in range(n):
        a += '9'
    for j in range(m):
        a += '8'
        
    print(a)

C++ Code:

#include <bits/stdc++.h>
using namespace std;
typedef long long int ll;
const int N=2e5+5;
int main(){
      int t;
      cin>>t;
      while(t--){
        int n,sum;
        cin>>n;
        sum=(n+3)/4;
        cout<<string(n-sum,'9')+string(sum,'8')<<endl;
    }
    return 0;
}


Comments

Submit
0 Comments
More Questions

112. Path Sum
1556A - A Variety of Operations
136. Single Number
169. Majority Element
119. Pascal's Triangle II
409. Longest Palindrome
1574A - Regular Bracket Sequences
1574B - Combinatorics Homework
1567A - Domino Disaster
1593A - Elections
1607A - Linear Keyboard
EQUALCOIN Equal Coins
XOREQN Xor Equation
MAKEPAL Weird Palindrome Making
HILLSEQ Hill Sequence
MAXBRIDGE Maximise the bridges
WLDRPL Wildcard Replacement
1221. Split a String in Balanced Strings
1002. Find Common Characters
1602A - Two Subsequences
1555A - PizzaForces
1607B - Odd Grasshopper
1084A - The Fair Nut and Elevator
1440B - Sum of Medians
1032A - Kitchen Utensils
1501B - Napoleon Cake
1584B - Coloring Rectangles
1562B - Scenes From a Memory
1521A - Nastia and Nearly Good Numbers
208. Implement Trie